如何使用for循环将数据从csv表插入到sql数据库?

这是我正在使用的示例csv文件:

Column1,Column2,Column3
data1,data2,data3
data1,data2,data3
data1,data2,data3
data1,data2,data3

我的程序的目的是通过命令行将该表插入到php文件中,并将数据插入到SQL数据库中。我把这个项目作为学习如何使用MySql的一种方式。

获取csv文件,然后将数据转换为一个或多个数组。然后创建一个数据库,并将数据插入到表中。

我只得到一行空值,而不是插入我的数据。

<?php

/**
 * Created by PhpStorm.
 * User: 
 * Date: 6/16/2017
 * Time: 11:32 AM
 */

$servername = "localhost";
$username = "pop-user";
$password = "pop-pw";
$database = 'popdb';

parse_str(implode('&', array_slice($argv, 1)), $_GET);
$file = array_map('str_getcsv', file($argv[1]));

// connecting to MySQL
$link = mysqli_connect($servername,$username,$password);

// check if connection completed
if ($link->connect_error) {
    die("Connection failed: ". $link->connect_error);
}

//creating database
printf("Creating database...\n");
$dbcheck = mysqli_select_db($link, $database);

// if database doesn't exist, then one will be created
if (!$dbcheck) {
    $sql = 'CREATE DATABASE '. $database;
    if (mysqli_query($link, $sql)) {
        echo "Database ". $database ." created\n";
    }
    else {
        echo "Failed to create database:\n";
        echo $link->error."\n";
    }
}

printf("Creating table...");
//creating table to hold information
$sql = 'USE '. $database. ';';
printf("\r\n");
mysqli_query($link,$sql);


$sql2 = "CREATE TABLE popCensus (";
foreach ($file[0] as $rows) {
    if ($rows != end($file[0]))
        $sql2 .= "{$rows} varchar(33), ";
    else
        $sql2 .= "{$rows} varchar(33)";
}
$sql2 .= ");";

echo $sql2;
printf("\r\n");
mysqli_query($link,$sql2);

printf("Inserting data into table...\n");
$cnt = 1;
$sql3 = "";
//Not inserting data
foreach ( $file as $file[$cnt]) {
    $sql3 = "INSERT INTO popcensus VALUES ( ";
    foreach ($file[$cnt] as $rows) {
        if ($rows != end($file[$cnt]))
            $sql3 .= "{$rows} , ";
        else
            $sql3 .= "{$rows});";
    }
    printf($sql3);
    printf("\n");
    mysqli_query($link, $sql3);
    $cnt++;
    printf("cnt: ". $cnt."\n");
    $sql3 = "";
}

printf("\nDone\n");
mysqli_close($link);
?>

编辑:我能够将信息解析成数组数组。我遇到的问题是试图在之后将它们插入到表中。

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